Product of Two Continuous Functions 0 Almost Everywhere

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Space of bounded and almost everywhere continuous function is complete?

• Thread starter 김찬우
• Start date Dec 7, 2021

• #1

김찬우 Asks: Space of bounded and almost everywhere continuous function is complete?
There is a well-known result that space of bounded and continuous function is complete. However, I was wondering if the same result would hold if it changes to space of bounded and almost everywhere continuous function is complete, given for those measure 0 points are not defined.

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• GisUser
• 6 minutes ago
• Technology Forum
• Replies: 0

GisUser Asks: Enable mouse wheel zoom on iframe mviewer map
I have an interactive map designed under mviewer package in iframe on my website exactly like here. Is there a way to enable mouse wheel zoom when the pointer is over the map?

SolveForum.com may not be responsible for the answers or solutions given to any question asked by the users. All Answers or responses are user generated answers and we do not have proof of its validity or correctness. Please vote for the answer that helped you in order to help others find out which is the most helpful answer. Questions labeled as solved may be solved or may not be solved depending on the type of question and the date posted for some posts may be scheduled to be deleted periodically. Do not hesitate to share your thoughts here to help others.

• FumbleFingers
• 6 minutes ago
• Technology Forum
• Replies: 0

FumbleFingers Asks: Grub-Customizer not updating Grub menu on dual-boot system
My brother's PC has a 128Gb SSD that originally contained just one copy of Mint 20 (which I'll call "OLDmint").

I booted from a "Live" Mint installation USB memory stick and used the Disks utility to "shrink" the original partition to 40Gb. Then I installed a second copy of Mint 20 (which I'll call "NEWmint") alongside OLDmint.

Everything works as expected except it always boots by default into NEWmint, which I don't seem to be able to change.

I used Software Manager (within NEWmint) to install Grub Customiser, then used that to delete the unwanted "Advanced Options" and move the OLDmint boot option up to the top of the list so as to make that the default.

But that Grub menu change made within NEWmint isn't reflected in the boot options. I installed Grub Customiser on OLDmint and tried to run it, but all options seem to be greyed out (and the display doesn't show thereflect changes made under NEWmint). I also ran sudo update-grub from the command line, but that made no difference.

I don't really understand UEFI. The PC bios has both UEFI and "non-UEFI" boot options for the SSD, but changing this makes no difference. I think those same (UEFI Y/N) options were available when booting from the Mint Live USB memory stick to install NEWmint, but I can't remember which I chose.

I could probably resolve this problem if I had my brother's PC in front of me. But he's hundreds of miles away, very "non-technical", and only available for (voice-only) telephone support sporadically. It's taken a long time to get as far as we have.

The reason I want this second copy of Mint is simply so my brother can override the Grub default periodically (using Down Arrow) to boot into NEWmint and use fsarchiver for system backups. That's how my own PC is set up, and I find it really easy to use. My "NEWmint" is only normally used to run the same single backup command every time, so I just open a Terminal, Up Arrow to the previous command, re-execute it, then boot back into my normal system.

Live / OLD / NEW Mint above are all Version 20. I think I had some kind of issue relating to Grub Customiser under latest Mint21 when I upgraded my own PC a couple of months ago. But whatever it was (I've forgotten - maybe it wasn't originally in the repository) I obviously got around that problem. I think it was entirely to do with Mint 21, though, so it's probably irrelevant.

How can I ensure my Grub menu changes are reflected in all other copies of Linux on the same machine (and by the actual boot process!

SolveForum.com may not be responsible for the answers or solutions given to any question asked by the users. All Answers or responses are user generated answers and we do not have proof of its validity or correctness. Please vote for the answer that helped you in order to help others find out which is the most helpful answer. Questions labeled as solved may be solved or may not be solved depending on the type of question and the date posted for some posts may be scheduled to be deleted periodically. Do not hesitate to share your thoughts here to help others.

• Saturanium
• 6 minutes ago
• Technology Forum
• Replies: 0

Saturanium Asks: All ubuntu-based distros freeze on 2nd startup
For the last little while now, I've been having problems with my computer when it starts up again after sleeping. Every time that happens, the time it takes to freeze the computer varies. When that happens, even though I don't have an SD card inserted in my laptop's front slot, it seems as though that SD card processor indicator was constantly lit. The only way to manage it was to force-shutdown my computer. To be more specific, I'm running a Toshiba Satellite A305 with KDE Neon 22.04, an Ubuntu-based distro. I've had this problem with almost every Ubuntu-based distro, obviously including KDE Neon. Any permanent fixes for this?

Sincerely, SaturaniumYT

SolveForum.com may not be responsible for the answers or solutions given to any question asked by the users. All Answers or responses are user generated answers and we do not have proof of its validity or correctness. Please vote for the answer that helped you in order to help others find out which is the most helpful answer. Questions labeled as solved may be solved or may not be solved depending on the type of question and the date posted for some posts may be scheduled to be deleted periodically. Do not hesitate to share your thoughts here to help others.

• cjs1978
• 16 minutes ago
• Technology Forum
• Replies: 0

cjs1978 Asks: RxJS - merge two HTTP requests, but emit the outer one instantly
I am fairly new to Angular and RxJS, and I have a hard time wrapping my head around some aspects of RxJS operators. I have some code here (in a component):

Code:

                          this.salesService.getOrders().subscribe(orders => {   this.orders = orders;   this.orders.forEach((order, index) => {     this.salesService.getOrderCustomers(order.id).subscribe(customers => {       this.ordersData[index]['customerName'] = customers.map(c => {return c.name}).join(", ");     })   }); });                        

The nice thing about this is that when this.orders is used in a table in my template, it will be available immediately, and then the column containing the customer name will populate as each call to the getOrderCustomers service method completes.

My question is if the same can be expressed with pure RxJS, since the above does not seem to be the "RxJS way", and I would like to learn. Also, in order to isolate the fetching of customers in an effect in the NgRx ComponentStore, my understanding is that the above will not work because the effect method must return an observable.

I have attempted something along these lines:

Code:

                          this.salesService.getOrders().pipe(     mergeMap(response =>       from(response.orders).pipe(         concatMap((oneOrder: object) => {           return this.salesService.getOrderCustomers(oneOrder['id'])         }),         reduce((customers, customer) => [...customers, customer], []),         map(customerList => {              /*  ?? Here I would return 'response' with the customer name added into each order,                   but I have no indexing of the orders to work with */         })       )     ),                        

I have two problems - one, I do not know how to add the retrieved customer into the right place in the response.orders variable, and secondly, the outer observable does not seem to emit until all the inner requests are done. Is there any RxJS way to progressively change the outer observable from the inner observable while initially emitting the outer observable in its original state?

I have a feeling that I am approaching this from a wrong, un-Angular and un-RxJS way. Any input would be appreciated. Thank you in advance.

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